Controlling Stepper Motor With Websocket

[Khanh]

Thank you for sharing your experience!

[skippy226]

Khanh, sorry for my late response but I ended up getting it figured out. For anyone else with a similar problem adding .toFixed() (as it's seen in some of the examples) fixed my problem. Thank you for your response!

[Khanh]

could you please post your full code of web (php + html + javascript).
And do you see any log from PHPoC Debugger ?

[skippy226]

Hello! I've been struggling to control a stepper motor from a webpage. The example program that does this 08.pes_2405_touch_rotate works well but I was trying to adapt it so I could just use html buttons to rotate the motor. My code in index.php is the same as the example with the following being different.

Added this function

function raise_focus()
{
if(ws != null)
    if(ws.readyState == 1)
        ws.send(0, "-100\r\n"); //-100 sent just to test. Eventually it will be a variable
}

And this html button

<button id="raise" type="button" onclick="raise_focus();">Raise</button>

My task0.php looks like this:

<?php

if(_SERVER("REQUEST_METHOD"))
exit; // avoid php execution via http request

include "/lib/sd_340.php";
include "/lib/sd_spc.php";
include "/lib/sn_tcp_ws.php";

define("STEPPER_SID", 1);
define("STEPS_PER_REV", 200); // 200 steps per revolution (1.8 degree each step)
define("SPEED_LOWER_LIMIT", 32);
define("SPEED_UPPER_LIMIT", 100000);

spc_reset();
spc_sync_baud(115200);

spc_request_dev(STEPPER_SID, "set vref drive 12");
spc_request_dev(STEPPER_SID, "set mode 32");

ws_setup(0, "pes_2405_touch_rotate", "csv.phpoc");

while(1)
{
    $rbuf = "";
    if(ws_state(0) == TCP_CONNECTED)
    {
        $rlen = ws_read_line(0, $rbuf);
        $pos = (int)spc_request_dev(STEPPER_SID, "get pos");

        if($rlen)
        {
            $pos += (int)$rbuf;
            spc_request_dev(STEPPER_SID, "goto $pos 2000 1000k");
        }
    }
}

?>

My code doesn't seem to turn the stepper (it seems to do nothing) but I'm struggling to figure out what I'm doing wrong.

Thank you for your help!